(x^2+3x)+(y^2-4y)=-4

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Solution for (x^2+3x)+(y^2-4y)=-4 equation:


Simplifying
(x2 + 3x) + (y2 + -4y) = -4

Reorder the terms:
(3x + x2) + (y2 + -4y) = -4

Remove parenthesis around (3x + x2)
3x + x2 + (y2 + -4y) = -4

Reorder the terms:
3x + x2 + (-4y + y2) = -4

Remove parenthesis around (-4y + y2)
3x + x2 + -4y + y2 = -4

Solving
3x + x2 + -4y + y2 = -4

Solving for variable 'x'.

Reorder the terms:
4 + 3x + x2 + -4y + y2 = -4 + 4

Combine like terms: -4 + 4 = 0
4 + 3x + x2 + -4y + y2 = 0

The solution to this equation could not be determined.

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